The Cost of a Trip between Cedar Grove, Wisconsin and Oxford, Wisconsin

Wisconsin is known for its picturesque towns and scenic routes that are ideal for taking a long road trip. Cedar Grove, Wisconsin, and Oxford, Wisconsin are two towns that are situated at a distance of around 140 miles from each other. People who want to travel between these two towns often choose to go by car, and the cost of the trip depends on several factors. In this article, we'll discuss the different possible routes, the cost of each route, and the best option for a road trip between Cedar Grove and Oxford.

The Different Possible Routes

Before we delve into the cost of the trip, let's look at the different possible routes to travel between Cedar Grove and Oxford.

Route 1: Via WI-26 S

The first route involves traveling south on WI-26 S from Cedar Grove to Johnson Creek and then taking WI-16 W to reach Oxford. This route is around 140 miles long, and it takes around 2 hours and 23 minutes to travel without making any stops.

Route 2: Via WI-32 S

The second option is to travel south on WI-32 S from Cedar Grove to Sheboygan and then take I-43 S to reach Beloit. From there, you can take I-90 E and US-51 S to reach Oxford. This route is around 158 miles long, and it usually takes around 2 hours and 49 minutes to travel without any stops.

Route 3: Via WI-57 S & WI-23 W

The third option is to take WI-57 S from Cedar Grove to Plymouth and then take WI-23 W to reach Oxford. This route is around 116 miles long, and it takes around 2 hours to travel without taking any stops.

The Cost of the Trip

The cost of the trip between Cedar Grove and Oxford depends on several factors such as the distance, gas prices, and vehicle fuel efficiency. We'll assume that we're traveling in a sedan car with an average fuel efficiency of 25 miles per gallon, and the average gas price in Wisconsin is around $2.97 per gallon.

Cost of Route 1

To calculate the cost of traveling via WI-26 S, we'll divide the total distance of 140 miles by the car's average fuel efficiency of 25 mpg. The result is 5.6 gallons of gas required to make this trip. Multiplying 5.6 gallons with the current gas price of $2.97, the total cost is around $16.63.

Cost of Route 2

To calculate the cost of traveling via WI-32 S, we'll divide the total distance of 158 miles by the car's average fuel efficiency of 25 mpg. The result is 6.32 gallons of gas required to make this trip. Multiplying 6.32 gallons with the current gas price of $2.97, the total cost is around $18.80.

Cost of Route 3

To calculate the cost of traveling via WI-57 S & WI-23 W, we'll divide the total distance of 116 miles by the car's average fuel efficiency of 25 mpg. The result is 4.64 gallons of gas required to make this trip. Multiplying 4.64 gallons with the current gas price of $2.97, the total cost is around $13.80.

From the above calculations, it's clear that traveling via WI-57 S & WI-23 W will cost the least, followed by traveling via WI-26 S and then WI-32 S.

The Best Route

From the above cost analysis, it's clear that traveling via WI-57 S & WI-23 W is the most cost-effective route between Cedar Grove and Oxford. It's also important to note that this route is the shortest, taking only 2 hours without any stops.

However, if you prefer to take a more scenic route that involves more stops and sightseeing, traveling via WI-26 S could be a great choice. This route takes you through several small towns and rural areas, providing a glimpse of Wisconsin's rural life.

Conclusion

Overall, the cost of a trip between Cedar Grove and Oxford depends on several factors, including fuel efficiency, gas prices, and the chosen route. After analyzing the three possible routes, traveling via WI-57 S & WI-23 W is the most cost-effective and shortest option between these two towns. However, if you're in the mood for a more scenic route and have some time to spare, traveling via WI-26 S could be an excellent choice. Regardless of the route you choose, it's sure to be a memorable road trip experience through the beautiful state of Wisconsin.